Thermodynamic Efficiency Calculator
Calculate thermal efficiency for heat engines, theoretical Carnot efficiency, and coefficient of performance (COP) for refrigeration/heat pumps. Enter heat input/output, work, or reservoir temperatures and choose your formula. Results include percent efficiency and step-by-step math.
Heat engine: η = W_out / Q_in = 1 - Q_c/Q_h
Carnot limit: η_Carnot = 1 - T_c / T_h
COP: refrigerator = Q_c / W_in ; heat pump = Q_h / W_in
Thermodynamic efficiency: fundamentals, Carnot limit and practical considerations
Thermodynamic efficiency is a central concept in energy conversion. It quantifies how effectively a device converts heat into useful work (heat engines) or moves heat using work (heat pumps and refrigerators). This article explains principal definitions, theoretical limits such as the Carnot efficiency, common practical loss mechanisms, and how to interpret and improve real-world performance.
Key definitions
Thermal efficiency (η) of a heat engine is defined as the ratio of work output (W_out) to heat input from the hot reservoir (Q_in):
η = W_out / Q_in = 1 - Q_c / Q_h
Here Q_h is the heat absorbed from the hot reservoir and Q_c is heat rejected to the cold reservoir. Efficiency ranges from 0 to 1 (or 0–100%).
Carnot efficiency — the theoretical maximum
The Carnot efficiency represents the highest possible efficiency for any reversible heat engine operating between two reservoirs at temperatures T_h (hot) and T_c (cold), provided temperatures are in Kelvin:
η_Carnot = 1 - T_c / T_h
No real engine can exceed this value because real processes are irreversible and produce entropy. Carnot teaches that raising T_h or lowering T_c increases maximum possible efficiency, but practical and material limits bound achievable temperatures.
Coefficient of performance (COP)
For devices that move heat (refrigerators, heat pumps), COP is the more useful metric. For a refrigerator:
COP_ref = Q_c / W_in
For a heat pump delivering heat to a warm space:
COP_hp = Q_h / W_in = COP_ref + 1
COP values can be greater than 1 because moving heat consumes less work than the heat quantity moved.
Sources of inefficiency
- Irreversible processes (friction, turbulence) increase entropy and lower efficiency.
- Heat losses (conduction, radiation) reduce useful heat available.
- Non-ideal working fluids and cycle deviations (finite heat transfer, pressure drops).
- Auxiliary power demands (pumps, fans) which subtract from net output.
Practical examples and units
Thermodynamic calculations often use kilojoules (kJ) or joules (J) for heat and work. Power units (kW) are energy per unit time. Always keep units consistent — this calculator converts common units for you. Percent efficiency is simply η × 100%.
Improving performance
- Increase the temperature of the heat source (higher T_h) where materials allow.
- Reduce heat sink temperature (lower T_c) where possible.
- Minimize irreversibilities: improve heat exchanger design, reduce frictional losses.
- Recover waste heat (combined heat and power) to improve overall system efficiency.
Worked example
A steam turbine receives 2500 kJ of heat (Q_in) and rejects 1800 kJ (Q_c). The useful work is W = Q_in − Q_c = 700 kJ. Thermal efficiency η = 700/2500 = 0.28 = 28%.
Limitations and safety
Calculations here are for idealized balances. For plant design and safety-critical engineering, perform detailed thermodynamic and mechanical analysis and follow regulatory standards.
Frequently Asked Questions
No — efficiency over 100% would violate the first and second laws of thermodynamics. COP can exceed 1 but it measures heat moved per unit work, not energy conversion efficiency.
Carnot's formula requires absolute temperature units (Kelvin) because it derives from entropy which depends on absolute temperature.
Only in an ideal reversible engine with no losses — real engines always have lower efficiency.
1 kcal = 4.184 kJ. This calculator supports kJ, J and kcal conversions.
Exergy measures the maximum useful work obtainable when a system comes to equilibrium with the environment. It accounts for both energy quantity and quality.
Higher T_h raises the Carnot limit, but material limitations and increased losses at high temperature may offset gains.
Yes — convert power rates (kW) to energy over the same time interval or use instantaneous power ratios: η = P_out / P_in_heat.
Regeneration (preheating working fluid using exhaust heat) can increase cycle efficiency by reducing required heat input.
Yes — COP depends strongly on reservoir temperatures; lower temperature lifts increase COP for heat pumps in many cases.
For teaching, quick estimates, homework checks, and conceptual engineering comparisons. Not a substitute for detailed design tools.